Leetcode

17.letterCombinationsOfAPhoneNumber.py

class Solution:
    def letterCombinations(self, digits: str) -> List[str]:
        mapping = {
            "2": ["a", "b", "c"],
            "3": ["d", "e", "f"],
            "4": ["g", "h", "i"],
            "5": ["j", "k", "l"],
            "6": ["m", "n", "o"],
            "7": ["p", "q", "r", "s"],
            "8": ["t", "u", "v"],
            "9": ["w", "x", "y", "z"],
        }
        res = []
        if not digits:
            return res

        def backtrack(index, current):
            if index == len(digits):
                res.append("".join(current))
                return
            for letter in mapping[digits[index]]:
                current.append(letter)
                backtrack(index + 1, current)
                current.pop()

        backtrack(0, [])
        return res


# class Solution:
#     def letterCombinations(self, digits: str) -> List[str]:
#         res = []
#         mapping = {
#             "2": ["a", "b", "c"],
#             "3": ["d", "e", "f"],
#             "4": ["g", "h", "i"],
#             "5": ["j", "k", "l"],
#             "6": ["m", "n", "o"],
#             "7": ["p", "q", "r", "s"],
#             "8": ["t", "u", "v"],
#             "9": ["w", "x", "y", "z"],
#             # "0": [" "],
#             # "1": []
#         }

#         def dfs(i, current):
#             if i == len(digits):
#                 if len(current) > 0:
#                     res.append(current)
#                 return
#             if i > len(digits):
#                 return

#             for letter in mapping[digits[i]]:
#                 dfs(i + 1, current + letter)

#         dfs(0, "")

#         return res